## Overview

### Question

$$n!$$ means $$n \times (n − 1) \times ... \times 3 \times 2 \times 1$$.

For example, $$10!$$ = 10 9 ... 3 2 1 = 3628800, and the sum of the digits in the number $$10!$$ is 3 + 6 + 2 + 8 + 8 + 0 + 0 = 27.

Find the sum of the digits in the number $$100!$$.